Ir Pieter Torbijn passed away on the 13th of June 2007.
We decided to dedicate this competition to him. We believe he would have enjoyed this competition very much considering his compassion for symmetry.
We received the problem from Stefano Popovski. When we asked him if he would allow us to dedicate the problem to Pieter Torbijn, he replied: "Of course this is a great loss and for sure you have my permission to dedicate the competition to Pieter, we all will miss his articles, theoretical comments and valuable solutions for so many problems! Whatever you think would serve to honor such a memorable person will be all right."
complete set of pentominoes is to be used:
Construct a closed chain using all pentominoes in which every pentomino has
at least two neighbors, where the combination with such a neighbor contains
an axis of symmetry. Thus A and B form a symmetrical shape; so do B and C, C
and D, … K and L and finally L and A as well.
The pentominoes must all be placed in the same flat area, just like the axes of symmetry.
Stefano sent us an example to clarify the problem.
Each blue line indicates an axis of symmetry between two bordering pieces. Just for the borders between red and green pieces there is no axis of symmetry present. Try to find as many solutions as possible. We’ll be very satisfied already when you just find one solution though!
On the next link you can find all combinations of two different pentominoes that contain an axis of symmetry.
Using spreadsheet can help to find solutions.
In order to use it, you can first save this excel file on your hard disk, then you can select any pentomino, move it around with the mouse and rotate or mirror it using the function ‘pentomino’